Calculate the speed of the sun and moon

Copy and paste to Expression to calculate:

Math.PI*2*149.6/24

- Speed of the sun for the sun to stand still in the sky

Math.PI*2*149.6/12

- Speed of the sun for the sun to move backwards in the sky

(Math.PI*2*384.4)/24

- Speed of the moon to stand still in the sky

If the sun moved 180° around the earth other than at the equinox the earth must turn to keep the same season on earth. Joshua's long day depicts just such a turn. If the earth turned 70° to keep the same season on earth, the poles would move 3,500 kilometers. If earth turned at the same time the sun moved the 180° there would be some hours plus or minus the 12 hours made by the sun moving 180°. Joshua's long day would be +12 hours + 4.6 hours = +16.6 hours of extra daylight a 22.6 hour day of daylight. Earth must shift 67° clockwise to keep in the same February 25 season. (Likewise a November or May sun miracle, not Joshua's long day, and there must be a counterclockwise shift say 4 less daylight hours the first time and 4 hours more daylight the second time.) At the 45th latitude there would be 10 hours daylight just before the sun moved. Then 14 hours right after Joshua's long day because of the sun to earth angle. However there could not be both 4.6 hours more daylight due to earth's shift and an August 31 7PM sunset instead of 5PM because both counter eachother. The counter is equal because sun rise at 5AM and sunset at 7PM in the August 31 inclination is the same 4 hours extra daylight as the 4.6 hours while earth shifted to keep in the same season. The first time earth must shift 67° clockwise and there would be 4 more hours spread out over the shift period. When the sun moved back again on August 31 1238 BC, see Judges 4, 5, 6, 7, 8, and Joshua 11, earth's axis must shift 67° counterclockwise and there would be 4 less hours daylight spread out over the shift period. Then the north pole must move 3,500 kilometers clockwise February 25 1238 BC and 3,500 kilometers counterclockwise August 31 1238 BC to keep in the same season. This would make 4 hours more daylight in the America's perhaps spread out over several hours immediately following the sun miracle on Joshua's long day. The forces of gravity and acceleration and centrifugal force must have been strongly countered by God to accomplish this shift.

Papyrus Anastasi IV 1279 BC "The sun it has come to pass riseth not...winter is come instead of summer...the months are reversed...the hours are disordered." If this quote from the Papyrus Anastasi was Moses' three days darkness, March 1279 BC last month of winter, after 36 hours of no sun it would have gotten cold like winter. Also the Egyptians had three seasons. The winter season ended about March 20 Julian. Egypt may have gone into a reverse orbit. However, if the sun set suddenly 180° at noon in the west, then moved 540° east with earth's rotation to stay on the opposite side of earth for the three days darkness, earth would not go into a reverse orbit because the sun would move back to where it was before. Nevertheless if the months were reversed that would mean a reverse orbit. That night what had been the summer night sky would become what had been the winter night sky. Thus there would be three days of darkness, 3X12 hours or 36 hours. Thus "the hours are disordered" because of the 36 hours extra darkness and the loss of 6 hours daylight at the sudden sunset March 1279 BC.
There is a problem with the shift period being more than a day. Days of the calendar must continue as they would have. That is, if the shift period were over a week, on the first day Egypt/Israel would be in the May 10 season, earth's inclination to the sun. At midweek earth would be in the March 21 season and at week end it would be March 3 meanwhile earth had overshifted to the February 25 season. Therefore either earth shifted on the first or second day, or earth shifted 35° instead of 45° by March 3, earth's inclination to the sun then catching up to the March 31 season. Much rather the shift must have been made by or on the next day. Joshua's long day is followed exactly half an orbit later with a sun/moon miracle August 31. Thus earth must have shifted 67° clockwise within 24 hours for the second sun miracle to need to be exactly half an orbit later when earth would again shift 67° counterclockwise, shift back to its regular 1238 axis/pole position and continue as if nothing had happened. likewise the sun miracle in Yao's 70th year on January 26 2287 BC was followed by a sun miracle on the anniversary of the same day January 26 2284 BC.
Also part of Papyrus Anastasi IV: "your face Turns towards me, raising Sun, which lights the mountains of your beauty, Disque étincelant among the men, who drives out darkness of Egypt. You have the shape of your Father * when it rises to the sky and your rays penetrate in all countries; there is which is private of your Beauties, because your words regulate the destinies of all the countries, gracious Seigneur who gives to all the breath Life". The Egyptians were very aware of the sun's movements.

"In his (King Yin's) second year (312 BC), in the country of Ts'e, the ground where they measured the length of the sun's shadow lengthened more than ten cubits, and was elevated a cubit."
This means the sun must have travelled 180° along the ecliptic plane to the other end of earth's axis tilt. So that instead of earth tilting away from the sun it was tilted toward the sun. If the sun traveled 180° west about autumn the sun would rise to the summer solstice position at noon if the sun started moving at sunrise. If the sun moved 180° east about the vernal equinox likewise the sun would pass through the summer solstice height. The sun could stand still as it did for Joshua, traveling 180° east with earth's rotation on the ecliptic plane, at noon and the sun rise and fall this cubit. However the shadow was lengthened 10 cubits suggesting if the sun moved 180° east it did so in a few hours passing the noon position from the west to the eastern horizon. Or perhaps earth did not immediately shift at the same time as the sun moved to keep in the same season. If this was November 6 or February 6 on our calendar (45 days after the autumn equinox or 45 days after the winter solstice) when the sun set suddenly in the west by moving 180° and the sundial, the gnomon, one cubit high; then the day following the gnomon must be raised one cubit higher to cast the same shadow on the sundial inorder to keep time until the next day when earth had turned back to keep in the same season. Thus there are many posible combinations.

The 12 circles on Senmut's celestial ceiling are supposed to depict the 12 feast days of the 12 months of the zodiac. However, this zodiac is reputed to move in reverse, and if so, a shift in earth's axis is necessary. Earth must have turned 75° counterclockwise for earth's axis to turn up the spear of the herdsman. Then the sun must have moved 180° in November or May and earth turned soon after to keep in the same season. These circles in divisions of 24, depict 12 cusps the hours of the day and night. If the sun moved 180° in November or May 2300 BC earth must shift its axis to point to Hercules. Yao's canon depicts stars 20° off marking the four seasons. If the sun moved 180° March 31 - eleven days before the vernal equinox on April 11 2357 BC earth must turn this 22° clockwise to stay in the same March 31 season. Howbeit these four stars must both reverse spring and fall and revolve in reverse - and then the sun be in the east in Scorpius in spring as the Chinese believed. Earth must turn 2 X the number of days after or before the equinox, 2 X (11) days is 22°. Earth must turn 20° to point more than several centuries more recent according to earth's precession and according to the measurements of James Legge. Thus the 800 BC orientation, 22° shift, works to make the stars of Yao's canon appear at dark directly overhead to mark the four seasons. Then 2 X 11 days = 22° and Yao's long day March 31 2357 BC. James Legge noted in the Chinese Classics in Yao's Canon that according to the sky in 2357 BC from the noon sun in summer in Leo, the sun had been in the west in Taurus in spring "But the vernal mansions go to the west and the autumnal ones to the east, reversing the previous directions of these two seasons, and in opposition to the prevailing notion of the Chinese that the spring belongs to the east." Chinese Classics, III, p.94 This describes the sun moving 180° east March 31 2357 BC from Taurus to Scorpius - and progressing in reverse through the year in the reverse orbit: thus "reversing the previous directions of these two seasons". Then the sun would appear to travel through the year through the zodiac from east to west like the sun travels each day from east to west. In a normal orbit almost everyone knows the stars that disappear in the west each night soon are no longer visible weeks later disappearing into the sun because the sun appears to travel from west to east in our normal counterclockwise orbit of the sun.

Copy and paste to Expression to calculate acceleration:
((4000000/(24*60*60))*2)/(12*60*60)

There has been a mistaken belief we had a 360 day year before 700 BC. There were 36 10 day weeks but 5 days were added at the end of each year. Try the calculations below. The change in the sun's heat is 10X the change in distance. Therefore you can see the heat would be severe. Then earth must have stayed in the same orbital path, the same distance from the sun, howbeit in reverse. Earth's orbit must have been sped up rather than earth's rotation slowed. If the earth slowed to 364 rotations from 366 rotations oceans would be lowered 800 feet at the equator. Earth must have sped up in its orbit, keeping the same orbital path, 48 hours. This would make 364 rotations in a year in a reverse orbit keeping the 365 solar day year. The Sothis period is based on the 365 day calendar. Also about 1250 BC the Chinese calculated the period between the winter solstice and the summer solstice to be 548 days when we see it is exactly 547.85 days (1.5 X 365.25) - Joseph Needham. If a gravitational force pulled the earth around the sun faster there may be no problem.

Earth must have sped up 380 mph to reach year end 48 hours sooner. Earth's speed around the sun is 67,000 mph. Earth speeds up in its elliptical orbit as it nears the sun. However, days from equinox to equinox are the same. Then if earth orbited the sun, keeping in the same elliptical path as before, 380 mph faster earth would complete one revolution, orbit, 48 hours sooner. We do not feel the affect of being pulled a few days faster around the winter season so we should not expect to feel the affect of being pulled a few days faster around the sun overall. See www.analemma.com The moon would need to speed up because its orbit would be against earth' s orbit. That is, earth's rotation would be against earth's reverse orbit and for the number of days in a lunar month to be the same 29.5 days the moon must slow down two less orbits of earth a year. Earth must speed up its orbit of the sun 380 miles per hour, 48 hours a year, in reverse. From about 70,000 mph to 70,380 mph. However, the moon would have to slow down in its orbit of the earth by the same amount 380 miles per hour because orbit is against orbit. From 3,600 kilometers an hour to 3,100 kilometers an hour. The moon must slow down its orbit of the earth for there to be 29.5 days a lunar cycle in a sped up reverse orbit of the sun. Even so, each lunar month must be 4 hours shorter than normal equaling the same number of lunar cycles, same number of days to a lunar cycle in a 48 hour sped up reverse orbit of the sun. There are 27.3 days for the moon to complete an orbit around the earth. In one year of a reverse orbit the moon would completely orbit earth 50 days slower than a normal year. There must have been at least 200 years of reverse orbits since 3000 BC. Then the moon would have orbited earth 10,000 days slower, 340 lunar orbits less, than normal in that period. Earth would orbit the sun one year faster in the same period. Thus earth has a few years of missing time and the moon has thousands of days of elapsed time. The moon orbits earth in an elliptical orbit every 29 days 5 hours to 29 days 20 hours, with an average of 29 days 12 hours. That is an average speed of 2,120 mph. Then the moon must slow its orbit 500 kilometers an hour, to 3100 kilometers an hour from 3600 kilometers an hour, during the period of earth's reverse orbit. Then the dates of the phases and appearing of the moon would have lined up with the days/nights and dates in our calendar BC. Moreover, earth is nearest the sun January 3 2008 and earth's orbit is fastest then. This means not only does there need to be a second sun miracle for the sun to move back and earth flow out of the reverse orbit, there needs to be a second reverse orbit, four sun miracles, to correct for missing time. In 1238 BC February 25 was at the beginning of earth's slowed down part of orbit. Earth was nearest the sun November 25. Then there would be more than thirty minutes of missing time when the sun returned August 31 and earth flowed into a regular orbit. Eclipse paths would be 32 minutes out meaning people would not see the eclipse by thousands of miles from where we would expect them to see the total eclipse. This had to be corrected with a second reverse orbit that began the day the first reverse orbit ended or there would be this error in recorded eclipse records. This because earth continued to rotate as usual. Thus the 187 days of half an orbit must be counted by 178 days of half an orbit to average 365.24 days in a year. 187/365.24 X 48 = 24:34 hours of missing time. Countered by + 12 hours going into the reverse orbit and + 12 hours coming out of it, leaving 32 minutes to be countered by a second reverse orbit. Then if the sun returned on the anniversary of the first sun miracle there would be no left over missing time. Two +12 hour long sun miracles as the sun moved 180° east both times would counter the 48 hours of missing time. Also if the sun moved 180° at the perihelion of the sun when the sun is nearest the earth or at the aphelion when the sun is farthest from the earth there would not need to be a second correcting reverse orbit. However, with 48 hours short every year in a reverse orbit time cannot itself line up with the calendar BC.

Earth must keep in the same elliptical path and distance from the sun in reverse, howbeit at a 380 mph faster orbit. There is no other way:

Math.sqrt((148.3/149.6)*(148.3/149.6)*(148.3/149.6))*365
-Days of the year if earth was 1,300,000 kilometers closer to sun

Math.sqrt((146.9/149.6)*(146.9/149.6)*(146.9/149.6))*365
-Days of the year if earth was 2,700,000 kilometers closer to sun

If the earth slowed its rotation:

You can visualize the enormous forces to move the sun at these high speeds. Meteorites could be hurled at earth as a result. Now experiment with: Terrestrial Impact Crater Dimensions

Here is the gravitational attraction formula:

It has been shown that if you are sitting outside a mass, the gravitational attraction you experience is identical to what you would see if all that mass were concentrated at the center of gravity.

            G.M1.M2

       F = ----------

              R^2

Where G is the gravitational constant, M1 and M2 are the masses,

and R the distance between their centers of Gravity.



If M1=ME, the mass of the Earth, and M2 = m, the mass of the body,

then, obviously,



            G.ME.m

       F = ---------

              R^2



Since G and ME always turn up together, we normally use the product



           a = G.ME

so

            a.m

       F = ------

            R^2

where

       a = 3.98602 x 10^14 m^3/sec^2